A jet of water with cross-sectional area A st | vedclass

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(B) The mass of water striking the wall per second is $m = A \cdot v \cdot \rho$.The initial momentum of the water striking the wall per second is $P_

Vedclass · Accepted Answer

$2Av^2 ho \cos 	heta$

Vedclass · Answer

(B) The mass of water striking the wall per second is $m = A \cdot v \cdot ho$.The initial momentum of the water striking the wall per second is $P_i = m \cdot v = Av^2 ho$.Since the collision is elastic,the water rebounds with the same speed $v$ at an angle $	heta$ with the normal. The component of momentum perpendicular to the wall is $P \cos 	heta$.The change in momentum per second (force) exerted by the wall on the water is $\Delta P = P_{final, x} - P_{initial, x}$.Taking the direction towards the wall as positive,the initial momentum component is $P_i \cos 	heta$ and the final momentum component is $-P_i \cos 	heta$.Therefore,the force exerted by the water on the wall is $F = |\Delta P| = |(-P_i \cos 	heta) - (P_i \cos 	heta)| = 2P_i \cos 	heta$.Substituting $P_i = Av^2 ho$,we get $F = 2Av^2 ho \cos 	heta$.

$A$ jet of water with cross-sectional area $A$ strikes a wall at an angle $\theta$ with the normal to the wall and rebounds elastically. If the density of water is $\rho$ and the velocity is $v$,what is the force exerted on the wall?

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