Two particles of masses 200 g and 500 g are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The velocity of the center of mass $\vec{V}_{cm}$ is given by the formula: $\vec{V}_{cm} = \frac{m_1 \vec{v}_1 + m_2 \vec{v}_2}{m_1 + m_2}$ Given:

Vedclass · Accepted Answer

$5 \ \hat{i} + \frac{25}{7} \ \hat{j}$

Vedclass · Answer

(C) The velocity of the center of mass $\vec{V}_{cm}$ is given by the formula: $\vec{V}_{cm} = \frac{m_1 \vec{v}_1 + m_2 \vec{v}_2}{m_1 + m_2}$ Given: $m_1 = 200 \ g$,$m_2 = 500 \ g$,$\vec{v}_1 = 10 \ \hat{i} \ m/s$,$\vec{v}_2 = 3 \ \hat{i} + 5 \ \hat{j} \ m/s$. Substituting the values: $\vec{V}_{cm} = \frac{200(10 \ \hat{i}) + 500(3 \ \hat{i} + 5 \ \hat{j})}{200 + 500}$ $\vec{V}_{cm} = \frac{2000 \ \hat{i} + 1500 \ \hat{i} + 2500 \ \hat{j}}{700}$ $\vec{V}_{cm} = \frac{3500 \ \hat{i} + 2500 \ \hat{j}}{700}$ $\vec{V}_{cm} = 5 \ \hat{i} + \frac{25}{7} \ \hat{j} \ m/s$.

Two particles of masses $200 \ g$ and $500 \ g$ are moving with velocities $10 \ \hat{i} \ m/s$ and $3 \ \hat{i} + 5 \ \hat{j} \ m/s$ respectively. The velocity of the center of mass of the system is:

Similar Questions

Obtain the general expression for the centre of mass of a system of $n$ distributed particles in three dimensions.

Four masses are arranged along a circle of radius $1 \ m$ as shown in the figure. The center of mass of this system of masses is at

Weights of $1\,g, 2\,g, \dots, 100\,g$ are suspended from the $1\,cm, 2\,cm, \dots, 100\,cm$ marks respectively of a light metre scale. Where should it be supported for the system to be in equilibrium?

Three equal masses are placed at $(0,0)$,$(a,0)$,and $\left( \frac{a}{2}, \frac{a\sqrt{3}}{2} \right)$. Find the coordinates of the center of mass.

Vedclass Test Series

Exam Paper Generator

Online Exam Module