(A) According to Wien's displacement law,$\lambda_m T = \text{constant}$.Therefore,$\lambda_1 T_1 = \lambda_2 T_2$.Given: $\lambda_1 = 11 \times 10^{-

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) According to Wien's displacement law,$\lambda_m T = \text{constant}$.Therefore,$\lambda_1 T_1 = \lambda_2 T_2$.Given: $\lambda_1 = 11 \times 10^{-5} \ cm$ and $\lambda_2 = 5.5 \times 10^{-5} \ cm$.Let the initial temperature be $T_1 = T$ and the new temperature be $T_2 = nT$.Substituting the values: $(11 \times 10^{-5}) \times T = (5.5 \times 10^{-5}) \times (nT)$.$11 = 5.5 \times n$.$n = \frac{11}{5.5} = 2$.Thus,the value of $n$ is $2$.

Class 11 Physics 10-2.Heat Transfer Spectral Emissive Power and Wien's Displacement Law

Medium

$A$ hot source emits maximum radiation energy at a wavelength of $11 \times 10^{-5} \ cm$. According to Wien's displacement law,for what value of $n$ will a source at a temperature $n$ times the original temperature emit maximum energy at a wavelength of $5.5 \times 10^{-5} \ cm$?

A
$2$
B
$4$
C
$0.5$
D
$1$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

10-2.Heat Transfer

Subtopic

Spectral Emissive Power and Wien's Displacement Law

In the figure,the distribution of energy density of the radiation emitted by a black body at a given temperature is shown. The possible temperature of the black body is ....... $K$.

Easy

View Solution

Ordinary bodies $P$ and $Q$ radiate maximum energy with a wavelength difference of $3 \mu m$. The absolute temperature of body $P$ is four times that of $Q$. The wavelength at which body $Q$ radiates maximum energy is (in $\mu m$)

MediumMHT CET 2024

View Solution

$A$ body at $1500 \ K$ emits maximum energy at a wavelength $20,000 \ \mathring{A}$. If the Sun emits maximum energy at a wavelength $5500 \ \mathring{A}$,then the temperature of the Sun is ....... $K$.

Difficult

View Solution

$A$ black body is at a temperature of $5760 \ K$. The energy of radiation emitted by the body at wavelength $250 \ nm$ is $U_1$,at wavelength $500 \ nm$ is $U_2$ and that at $1000 \ nm$ is $U_3$. Wien's constant,$b = 2.88 \times 10^6 \ nm \ K$. Which of the following is correct?

MediumNEET 2016

View Solution

If a graph is plotted by taking spectral emissive power along $y$-axis and wavelength along $x$-axis,then the area under the graph above the wavelength axis is ...........

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ hot source emits maximum radiation energy at a wavelength of $11 \times 10^{-5} \ cm$. According to Wien's displacement law,for what value of $n$ will a source at a temperature $n$ times the original temperature emit maximum energy at a wavelength of $5.5 \times 10^{-5} \ cm$?

Similar Questions

In the figure,the distribution of energy density of the radiation emitted by a black body at a given temperature is shown. The possible temperature of the black body is ....... $K$.

Ordinary bodies $P$ and $Q$ radiate maximum energy with a wavelength difference of $3 \mu m$. The absolute temperature of body $P$ is four times that of $Q$. The wavelength at which body $Q$ radiates maximum energy is (in $\mu m$)

$A$ body at $1500 \ K$ emits maximum energy at a wavelength $20,000 \ \mathring{A}$. If the Sun emits maximum energy at a wavelength $5500 \ \mathring{A}$,then the temperature of the Sun is ....... $K$.

$A$ black body is at a temperature of $5760 \ K$. The energy of radiation emitted by the body at wavelength $250 \ nm$ is $U_1$,at wavelength $500 \ nm$ is $U_2$ and that at $1000 \ nm$ is $U_3$. Wien's constant,$b = 2.88 \times 10^6 \ nm \ K$. Which of the following is correct?

If a graph is plotted by taking spectral emissive power along $y$-axis and wavelength along $x$-axis,then the area under the graph above the wavelength axis is ...........

Vedclass Test Series

Exam Paper Generator

Online Exam Module