During modulation,a transmitter supplies 9 k | vedclass

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(B) The total power radiated in an amplitude modulated wave is given by the formula: $P_t = P_c \left( 1 + \frac{m^2}{2} \right)$.Here,the carrier pow

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$9.72$

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(B) The total power radiated in an amplitude modulated wave is given by the formula: $P_t = P_c \left( 1 + \frac{m^2}{2} ight)$.Here,the carrier power $P_c = 9 \ kW$ and the modulation index $m = 40\% = 0.4$.Substituting these values into the formula:$P_t = 9 \left( 1 + \frac{(0.4)^2}{2} ight)$$P_t = 9 \left( 1 + \frac{0.16}{2} ight)$$P_t = 9 \left( 1 + 0.08 ight)$$P_t = 9 	imes 1.08 = 9.72 \ kW$.

During modulation,a transmitter supplies $9 \ kW$ to the antenna. Calculate the total power radiated during $40\%$ modulation in $kW$.

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