In an AM wave,the frequencies of LSB and USB | vedclass

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(B) The frequency of the $LSB$ is given by $f_c - f_m = 2.99 \ MHz$  ---$(1)$The frequency of the $USB$ is given by $f_c + f_m = 3.01 \ MHz$  ---$(2)$

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$3 \ MHz, 10 \ kHz$

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(B) The frequency of the $LSB$ is given by $f_c - f_m = 2.99 \ MHz$  ---$(1)$The frequency of the $USB$ is given by $f_c + f_m = 3.01 \ MHz$  ---$(2)$Adding equations $(1)$ and $(2)$:$(f_c - f_m) + (f_c + f_m) = 2.99 + 3.01$$2f_c = 6.00 \ MHz$$f_c = 3 \ MHz$Subtracting equation $(1)$ from $(2)$:$(f_c + f_m) - (f_c - f_m) = 3.01 - 2.99$$2f_m = 0.02 \ MHz$$f_m = 0.01 \ MHz = 10 \ kHz$Thus,the carrier frequency is $3 \ MHz$ and the modulating frequency is $10 \ kHz$.

In an $AM$ wave,the frequencies of $LSB$ and $USB$ are $2.99 \ MHz$ and $3.01 \ MHz$ respectively. The carrier frequency is ....... and the modulating frequency is .......

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