A carrier wave has a frequency of 1000 , kHz | vedclass

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Question

(A) Given: Carrier frequency $f_c = 1000 \, kHz$,Carrier amplitude $A_c = 20 \, V$. Signal frequency $f_m = 10 \, kHz$,Signal amplitude $A_m = 10 \, V

Vedclass · Accepted Answer

$0.5, 990 \, kHz, 1010 \, kHz$

Vedclass · Answer

(A) Given: Carrier frequency $f_c = 1000 \, kHz$,Carrier amplitude $A_c = 20 \, V$. Signal frequency $f_m = 10 \, kHz$,Signal amplitude $A_m = 10 \, V$. $1$. The modulation index $\mu$ is given by $\mu = A_m / A_c = 10 / 20 = 0.5$. $2$. The frequency of the Lower Sideband $(LSB)$ is $f_c - f_m = 1000 \, kHz - 10 \, kHz = 990 \, kHz$. $3$. The frequency of the Upper Sideband $(USB)$ is $f_c + f_m = 1000 \, kHz + 10 \, kHz = 1010 \, kHz$. Thus,the modulation index is $0.5$,$LSB$ is $990 \, kHz$,and $USB$ is $1010 \, kHz$.

$A$ carrier wave has a frequency of $1000 \, kHz$ and an amplitude of $20 \, V$. It is amplitude modulated by a signal wave of frequency $10 \, kHz$ and amplitude $10 \, V$. The modulation index and the frequencies of the $LSB$ and $USB$ are,respectively:

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