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(C) For a diode detector to follow the envelope of the amplitude modulated wave,the condition for the maximum modulation frequency $f_m$ is given by:$

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$10.62 \ kHz$

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(C) For a diode detector to follow the envelope of the amplitude modulated wave,the condition for the maximum modulation frequency $f_m$ is given by:$f_m = \frac{1}{2\pi m_a RC}$Given:$C = 250 \ pF = 250 	imes 10^{-12} \ F$$R = 100 \ k\Omega = 100 	imes 10^3 \ \Omega$$m_a = 60\% = 0.6$Substituting the values:$f_m = \frac{1}{2 	imes 3.14 	imes 0.6 	imes (100 	imes 10^3) 	imes (250 	imes 10^{-12})}$$f_m = \frac{1}{2 	imes 3.14 	imes 0.6 	imes 25 	imes 10^{-6}}$$f_m = \frac{1}{94.2 	imes 10^{-6}} \approx 10615.7 \ Hz$$f_m \approx 10.62 \ kHz$

$A$ diode detector is used to detect an amplitude modulated wave with $60\%$ modulation,using a capacitor of $250 \ pF$ in parallel with a resistor of $100 \ k\Omega$. What is the maximum modulation frequency that can be detected by this circuit?

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