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(D) For isotonic solutions,the osmotic pressures are equal,which implies the molar concentrations are equal: $C_1 = C_2$. Let $M$ be the molar mass of

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$50000$

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(D) For isotonic solutions,the osmotic pressures are equal,which implies the molar concentrations are equal: $C_1 = C_2$. Let $M$ be the molar mass of the protein. The concentration of protein is $\frac{500 \ g/L}{M \ g/mol} = \frac{500}{M} \ mol/L$. The molar mass of sugar $(C_{12}H_{22}O_{11})$ is $342 \ g/mol$. The concentration of sugar is $\frac{3.42 \ g/L}{342 \ g/mol} = 0.01 \ mol/L$. Equating the concentrations: $\frac{500}{M} = 0.01$. Solving for $M$: $M = \frac{500}{0.01} = 50000 \ g/mol$.

$A$ solution containing $500 \ g$ of protein per liter of solution is isotonic with a solution containing $3.42 \ g$ of sugar per liter of solution. The molar mass of the protein is:

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