The correct relationship between the osmotic | vedclass

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Question

(B) The osmotic pressure $(\pi)$ is a colligative property given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar conce

Vedclass · Accepted Answer

$\pi_{Na_2SO_4} > \pi_{NaCl}$

Vedclass · Answer

(B) The osmotic pressure $(\pi)$ is a colligative property given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature.For $0.1 \ M \ NaCl$,the dissociation is $NaCl ightarrow Na^+ + Cl^-$,so $i = 2$.Thus,$\pi_{NaCl} = 2 	imes 0.1 	imes RT = 0.2 \ RT$.For $0.1 \ M \ Na_2SO_4$,the dissociation is $Na_2SO_4 ightarrow 2Na^+ + SO_4^{2-}$,so $i = 3$.Thus,$\pi_{Na_2SO_4} = 3 	imes 0.1 	imes RT = 0.3 \ RT$.Comparing the two,$0.3 \ RT > 0.2 \ RT$,therefore $\pi_{Na_2SO_4} > \pi_{NaCl}$.

The correct relationship between the osmotic pressure of $0.1 \ M \ NaCl$ and $0.1 \ M \ Na_2SO_4$ is ......

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