To have an osmotic pressure equal to a soluti | vedclass

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Question

(B) For solutions to have the same osmotic pressure (isotonic),their molar concentrations must be equal: $C_1 = C_2$. Since $C = \frac{w}{M 	imes V}$

Vedclass · Accepted Answer

$4.60$

Vedclass · Answer

(B) For solutions to have the same osmotic pressure (isotonic),their molar concentrations must be equal: $C_1 = C_2$. Since $C = \frac{w}{M 	imes V}$,we have $\frac{w_1}{M_1 V_1} = \frac{w_2}{M_2 V_2}$. Given $w_2 = 9.2 \ g$,$V_2 = 1 \ L$,$V_1 = 0.5 \ L$,and the molar mass of glucose $(M_1 = M_2 = 180 \ g/mol)$. Substituting the values: $\frac{w_1}{180 	imes 0.5} = \frac{9.2}{180 	imes 1}$. $	herefore w_1 = \frac{9.2 	imes 180 	imes 0.5}{180} = 4.60 \ g$.

To have an osmotic pressure equal to a solution containing $9.2 \ g$ of glucose per liter,how many grams of glucose must be dissolved in $0.5 \ L$ of solution?

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