At $88\,^oC$,the vapor pressure of benzene is $900 \, \text{torr}$ and that of toluene is $360 \, \text{torr}$. What is the mole fraction of benzene in the mixture with toluene that will boil at $88\,^oC$ and $1 \, \text{atm}$ pressure,assuming it forms an ideal solution?

Consider the following statements about the solutions formed by mixing two liquids.
$A$. An ideal solution thus formed obeys Raoult's law throughout the composition range.
$B$. Mixture of chloroform and acetone shows negative deviation from Raoult's law.
$C$. Mixture of aniline and phenol shows positive deviation from Raoult's law.

On mixing $10 \ mL$ of acetone with $40 \ mL$ of chloroform,the total volume of the solution is

Which of the following is an ideal solution?

Which of the following will form an ideal solution?

At $373 \ K$,heptane and octane form an ideal solution. The vapor pressures of the two pure liquid components (heptane and octane) are $105 \ kPa$ and $45 \ kPa$,respectively. The vapor pressure of the solution formed by mixing $25 \ g$ of heptane and $35 \ g$ of octane is ........ $kPa$. (Molar masses of heptane and octane are $100 \ g \ mol^{-1}$ and $114 \ g \ mol^{-1}$,respectively.)