At 310 K,the osmotic pressure of blood is 7. | vedclass

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Question

(A) For isotonic solutions,the osmotic pressure $(\pi)$ is the same.Given: $\pi = 7.65 \ atm$,$T = 310 \ K$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$

Vedclass · Accepted Answer

$5.41$

Vedclass · Answer

(A) For isotonic solutions,the osmotic pressure $(\pi)$ is the same.Given: $\pi = 7.65 \ atm$,$T = 310 \ K$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$.Using the formula $\pi = CRT$,where $C$ is molarity $(mol/L)$:$C = \frac{\pi}{RT} = \frac{7.65}{0.0821 	imes 310} = \frac{7.65}{25.451} \approx 0.3006 \ mol/L$.Glucose $(C_6H_{12}O_6)$ has a molar mass of $180 \ g/mol$.Concentration in $g/L = C 	imes 	ext{Molar Mass} = 0.3006 	imes 180 = 54.108 \ g/L$.Since $1000 \ mL$ contains $54.108 \ g$,then $100 \ mL$ contains $5.41 \ g$.Therefore,the concentration is $5.41 \%$ (w/v).

At $310 \ K$,the osmotic pressure of blood is $7.65 \ atm$. An aqueous solution of glucose will be isotonic with blood at a concentration of ........ $\%$ (weight/volume).

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