The freezing point of a solution prepared by adding $8.1 \ g$ of $HBr$ ($90\%$ ionized) to $100 \ g$ of water is $...... \ ^\circ C$. (Given $K_f$ for water $= 1.86 \ K \ kg \ mol^{-1}$)

  • A
    $0.85$
  • B
    $-3.53$
  • C
    $0$
  • D
    $-0.35$

Explore More

Similar Questions

If $A_2 B$ is $30 \%$ ionised in an aqueous solution,then the value of van't Hoff factor $(i)$ is $............ \times 10^{-1}$.

The van't Hoff factor $(i)$ for a dilute aqueous solution of the strong electrolyte barium hydroxide is

$1$ molal aqueous solution of an electrolyte $A_{2}B_{3}$ is $60\%$ ionised. The boiling point of the solution at $1 \ atm$ is ......... $K$.
(Rounded-off to the nearest integer)
[Given $K_{b}$ for $H_{2}O = 0.52 \ K \ kg \ mol^{-1}$]

For a dilute solution of $K_3[Fe(CN)_6]$,the van't Hoff factor $(i)$ is ..... [assuming $100\%$ ionization]

What is the freezing point of a solution containing $8.1 \ g \ HBr$ in $100 \ g$ water,assuming the acid to be $90 \ \%$ ionised ($K_f$ for water $= 1.86 \ K \ kg \ mol^{-1}$)?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo