The molarity of the solution obtained by mixing $800 \ mL$ of $0.5 \ M$ $HCl$ and $200 \ mL$ of $1 \ M$ $HCl$ will be ....... $M$.

Concentrated $HCl$ is $10 \,N$. How can $1000 \,cc$ of $1 \,N \,HCl$ be prepared by dilution?

When $W_B \ g$ of solute (molecular mass $M_B$) is dissolved in $W_A \ g$ of solvent,the molality $m$ of the solution is:

$A$ compound $H_2X$ with molar weight of $80 \ g \ mol^{-1}$ is dissolved in a solvent having density of $0.4 \ g \ mL^{-1}$. Assuming no change in volume upon dissolution,the molality of a $3.2 \ M$ solution is:

The volumes of two $HCl$ solutions $A$ $(0.5 \, M)$ and $B$ $(0.1 \, M)$ to be mixed for preparing $2 \, L$ of $0.2 \, M \, HCl$ are

The mole fraction of a solute in a $1$ molal ethanolic solution is: