For $1000 \ g$ of $1,4$-dioxane,the cryoscopic constant $K_f = 4.9 \ K \ kg \ mol^{-1}$. What will be the depression in freezing point for a $0.001 \ m$ solution prepared in dioxane?
- A$0.0049$
- B$4.9 + 0.001$
- C$4.9$
- D$0.49$
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Similar Questions
Calculate the cryoscopic constant $(K_f)$ of a solvent if the depression in freezing point of a $0.4 \ m$ solution of a non-volatile solute is $1.8 \ K$.
What happens to the freezing point of benzene when a small quantity of naphthalene is added to it?
DifficultJEE MAIN 2024
View Solution Column-$I$ (Various solutions) Column-$II$ (Freezing point) $a$. $0.1 \, M \ BaCl_2$ solution $p$. $271 \, K$ $b$. $0.1 \, M \ NaCl$ solution $q$. $270 \, K$ $c$. $0.1 \, M \ K_3[Fe(CN)_6]$ solution $r$. $268 \, K$ $d$. $0.1 \, M \ Al_2(SO_4)_3$ solution $s$. $269 \, K$
Given: Freezing point of $0.1 \, M$ sucrose solution $= 272 \, K$ and freezing point of water $= 273 \, K$.
Which of the following options shows the correct matches?
| Column-$I$ (Various solutions) | Column-$II$ (Freezing point) |
|---|---|
| $a$. $0.1 \, M \ BaCl_2$ solution | $p$. $271 \, K$ |
| $b$. $0.1 \, M \ NaCl$ solution | $q$. $270 \, K$ |
| $c$. $0.1 \, M \ K_3[Fe(CN)_6]$ solution | $r$. $268 \, K$ |
| $d$. $0.1 \, M \ Al_2(SO_4)_3$ solution | $s$. $269 \, K$ |
Given: Freezing point of $0.1 \, M$ sucrose solution $= 272 \, K$ and freezing point of water $= 273 \, K$.
Which of the following options shows the correct matches?
Medium
View Solution$A$ solution containing $62 \ g$ of ethylene glycol in $250 \ g$ of water is cooled to $-10 \ ^\circ C$. If $K_f$ for water is $1.86 \ K \ kg \ mol^{-1}$,the amount of water (in $g$) separated as ice is:
DifficultJEE MAIN 2019
View SolutionThe freezing point of an aqueous solution containing $17 \ g$ of $C_2H_5OH$ in $1000 \ g$ of water is ......... $^oC$. (Given $K_f$ of water $= 1.86 \ K \ kg \ mol^{-1}$)
Medium
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