The center of mass of three particles of masses $10 \ kg, 20 \ kg$,and $30 \ kg$ is at $(0, 0, 0)$. Where should a fourth particle of mass $40 \ kg$ be placed so that the center of mass of the system shifts to $(3, 3, 3)$?

  • A
    $(0, 0, 0) \ m$
  • B
    $(7.5, 7.5, 7.5) \ m$
  • C
    $(1, 2, 3) \ m$
  • D
    $(4, 4, 4) \ m$

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