$A$ gas at $27^{\circ}C$ has a volume $V$ and pressure $P$. If it is heated such that the pressure becomes double and the volume becomes triple,what is the final temperature in $^{\circ}C$?

The volume of a gas will be double of what it is at $0^{\circ}C$ (pressure remaining constant) at:

The temperature of an open room of volume $30\ m^3$ increases from $17^\circ C$ to $27^\circ C$ due to sunshine. The atmospheric pressure in the room remains $1 \times 10^5\ Pa$. If $n_i$ and $n_f$ are the number of molecules in the room before and after heating,then $n_f - n_i$ will be:

The perfect gas equation for $4 \ g$ of hydrogen gas is

An ideal gas equation can be written as $P = \frac{\rho R T}{M_{0}}$,where $\rho$ and $M_{0}$ are respectively,

$A$ container holds $13 \, g$ of gas at a temperature of $27^{\circ}C$. If the temperature of the container is raised to $52^{\circ}C$ while keeping the pressure constant,the amount of gas that must be released is ..... $g$.