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(C) The pressure exerted by an ideal gas is given by the formula: $P = \frac{1}{3} \rho v_{rms}^2 = \frac{1}{3} \frac{M}{V} v_{rms}^2$.Since $P \propt

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$2P_0$

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(C) The pressure exerted by an ideal gas is given by the formula: $P = \frac{1}{3} ho v_{rms}^2 = \frac{1}{3} \frac{M}{V} v_{rms}^2$.Since $P \propto M \cdot v^2$,where $M$ is the total mass of the gas and $v$ is the root mean square velocity.Given: $M_2 = \frac{M_1}{2}$ and $v_2 = 2v_1$.Therefore,the ratio of pressures is: $\frac{P_2}{P_1} = \frac{M_2}{M_1} \left( \frac{v_2}{v_1} ight)^2$.Substituting the values: $\frac{P_2}{P_0} = \left( \frac{M_1/2}{M_1} ight) \left( \frac{2v_1}{v_1} ight)^2 = \frac{1}{2} 	imes (2)^2 = \frac{1}{2} 	imes 4 = 2$.Thus,$P_2 = 2P_0$.

The pressure exerted by a gas is $P_0$. If the mass of the molecules is halved and their velocity is doubled,the pressure will become .......

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