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(D) The volume of the cylinder is $V = 200 \ L = 200 	imes 10^{-3} \ m^3 = 0.2 \ m^3$.The total translational kinetic energy $E_k$ is given as $1.52

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$5 	imes 10^5$

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(D) The volume of the cylinder is $V = 200 \ L = 200 	imes 10^{-3} \ m^3 = 0.2 \ m^3$.The total translational kinetic energy $E_k$ is given as $1.52 	imes 10^5 \ J$.According to the kinetic theory of gases,the pressure $P$ is related to the translational kinetic energy per unit volume by the formula $P = \frac{2}{3} \frac{E_k}{V}$.Substituting the values into the formula:$P = \frac{2}{3} 	imes \frac{1.52 	imes 10^5}{0.2}$.$P = \frac{2}{3} 	imes 7.6 	imes 10^5$.$P \approx 5.06 	imes 10^5 \ N \ m^{-2}$.Rounding to the nearest given option,the pressure is $5 	imes 10^5 \ N \ m^{-2}$.

$A$ cylinder of capacity $200 \ L$ is filled with $H_2$ gas. The total average translational kinetic energy of the molecules is $1.52 \times 10^5 \ J$. Calculate the pressure of $H_2$ in the cylinder in $N \ m^{-2}$.

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