The rms speed of oxygen at 27^{circ}C will be | vedclass

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(A) Given temperature,$T = 27^{\circ}C = 273 + 27 = 300 \, K$.The molar mass of oxygen $(O_2)$ is $M_w = 32 	imes 10^{-3} \, kg/mol$ and the universa

Vedclass · Accepted Answer

$483.5$

Vedclass · Answer

(A) Given temperature,$T = 27^{\circ}C = 273 + 27 = 300 \, K$.The molar mass of oxygen $(O_2)$ is $M_w = 32 	imes 10^{-3} \, kg/mol$ and the universal gas constant is $R = 8.31 \, J \, mol^{-1} K^{-1}$.The formula for $rms$ speed is $v_{rms} = \sqrt{\frac{3RT}{M_w}}$.Substituting the values: $v_{rms} = \sqrt{\frac{3 	imes 8.31 	imes 300}{32 	imes 10^{-3}}}$.$v_{rms} = \sqrt{\frac{7479}{0.032}} = \sqrt{233718.75} \approx 483.44 \, ms^{-1}$.Thus,the $rms$ speed is approximately $483.5 \, ms^{-1}$.

The $rms$ speed of oxygen at $27^{\circ}C$ will be .... $ms^{-1}$.

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