The shortest wavelength emitted from an X-ray | vedclass

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Question

(A) The shortest wavelength (cutoff wavelength) of $X$-rays produced in an $X$-ray tube is given by the Duane-Hunt law: $\lambda_{min} = \frac{hc}{eV}

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The voltage applied across the tube

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(A) The shortest wavelength (cutoff wavelength) of $X$-rays produced in an $X$-ray tube is given by the Duane-Hunt law: $\lambda_{min} = \frac{hc}{eV}$.Here,$h$ is Planck's constant,$c$ is the speed of light,$e$ is the charge of an electron,and $V$ is the accelerating potential difference (voltage) applied across the tube.Since $h$,$c$,and $e$ are constants,the minimum wavelength $\lambda_{min}$ is inversely proportional to the applied voltage $V$.Therefore,the shortest wavelength depends on the voltage applied across the tube.

The shortest wavelength emitted from an $X$-ray tube depends on which of the following?

Similar Questions

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