When four hydrogen nuclei combine to form a h | vedclass

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(B) In the process of nuclear fusion, four hydrogen nuclei $(_1H^1)$ fuse to form one helium nucleus $(_2He^4)$. The mass of the resulting helium nucl

Vedclass · Accepted Answer

Energy is released.

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(B) In the process of nuclear fusion, four hydrogen nuclei $(_1H^1)$ fuse to form one helium nucleus $(_2He^4)$. The mass of the resulting helium nucleus is less than the sum of the masses of the four hydrogen nuclei. This mass defect $(\Delta m)$ is converted into energy according to Einstein's mass-energy equivalence principle, $E = \Delta m c^2$. Since the binding energy per nucleon for helium is higher than that of hydrogen, the process is exothermic, meaning energy is released.

When four hydrogen nuclei combine to form a helium nucleus, then:

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