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(B) In an $X$-ray tube, the intensity of the emitted radiation depends on the filament current, while the minimum wavelength $(\lambda_{min})$ depends

Vedclass · Accepted Answer

$3, 4$

Vedclass · Answer

(B) In an $X$-ray tube, the intensity of the emitted radiation depends on the filament current, while the minimum wavelength $(\lambda_{min})$ depends on the accelerating potential difference $(V)$.$1$. The intensity of the $X$-rays remains constant if the filament current is not changed.$2$. The minimum wavelength is given by the formula $\lambda_{min} = \frac{hc}{eV}$. As the potential difference $(V)$ increases, the minimum wavelength $(\lambda_{min})$ decreases.Therefore, the correct observations are that the intensity remains constant and the minimum wavelength decreases, which corresponds to statements $(3)$ and $(4)$.

When the potential difference applied to an $X$-ray tube is increased, the resulting emitted radiation shows:

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