In the nuclear reaction X(n, alpha) _3^7 Li,f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given nuclear reaction is $X + _0^1 n \rightarrow _2^4 He + _3^7 Li$.Applying the law of conservation of mass number:$A + 1 = 4 + 7$$A + 1 = 1

Vedclass · Accepted Answer

$_5^{10} B$

Vedclass · Answer

(A) The given nuclear reaction is $X + _0^1 n \rightarrow _2^4 He + _3^7 Li$.Applying the law of conservation of mass number:$A + 1 = 4 + 7$$A + 1 = 11$$A = 10$Applying the law of conservation of atomic number (charge):$Z + 0 = 2 + 3$$Z = 5$Thus,the element $X$ has mass number $10$ and atomic number $5$,which corresponds to Boron $(B)$.Therefore,$X = _5^{10} B$.

In the nuclear reaction $X(n, \alpha) _3^7 Li$,find the value of $X$.

Similar Questions

Is nuclear force short range or long range?

Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of

The mass of a neutron is approximately the same as that of:

The nuclear reaction is represented by $X(n, \alpha) \to _3^7Li$. Which element is $X$?

Who discovered the neutron?

Vedclass Test Series

Exam Paper Generator

Online Exam Module