_1H^1 + _1H^1 + _1H^2 to X + _1e^0 + text{Ene | vedclass

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(D) To find the particle $X$, we apply the laws of conservation of mass number and atomic number.For the atomic number $(Z)$:$1 + 1 + 1 = Z + 1 \impli

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$_2He^4$ (Alpha particle)

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(D) To find the particle $X$, we apply the laws of conservation of mass number and atomic number.For the atomic number $(Z)$:$1 + 1 + 1 = Z + 1 \implies 3 = Z + 1 \implies Z = 2$.For the mass number $(A)$:$1 + 1 + 2 = A + 0 \implies 4 = A$.Since the atomic number is $2$ and the mass number is $4$, the particle $X$ is $_2He^4$, which is an alpha particle.

$_1H^1 + _1H^1 + _1H^2 \to X + _1e^0 + \text{Energy}$. The emitted particle $X$ is ........?

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