The radius of a Germanium (Ge) nucleus is twi | vedclass

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(C) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number (number of nucleons).Given that the radius of the G

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$72$

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(C) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number (number of nucleons).Given that the radius of the Germanium nucleus $(R_{Ge})$ is twice the radius of the Beryllium nucleus $(R_{Be})$:$R_{Ge} = 2 	imes R_{Be}$Substituting the formula $R = R_0 A^{1/3}$:$R_0 (A_{Ge})^{1/3} = 2 	imes R_0 (A_{Be})^{1/3}$Given $A_{Be} = 9$,we have:$(A_{Ge})^{1/3} = 2 	imes (9)^{1/3}$Cubing both sides:$A_{Ge} = 2^3 	imes 9$$A_{Ge} = 8 	imes 9 = 72$Thus,the number of nucleons in Germanium is $72$.

The radius of a Germanium $(Ge)$ nucleus is twice the radius of a $^9_4Be$ nucleus. The number of nucleons in $Ge$ is ......

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