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(C) The initial nucleus is $_{72}X^{180}$.$1$. After $\alpha$-decay ($_{2}He^{4}$ emission),the mass number decreases by $4$ and the atomic number dec

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$172, 69$

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(C) The initial nucleus is $_{72}X^{180}$.$1$. After $\alpha$-decay ($_{2}He^{4}$ emission),the mass number decreases by $4$ and the atomic number decreases by $2$: $_{72}X^{180} \xrightarrow{\alpha} _{70}X_1^{176}$.$2$. After $\beta$-decay (emission of an electron,$_{ -1}e^{0}$),the mass number remains unchanged and the atomic number increases by $1$: $_{70}X_1^{176} \xrightarrow{\beta} _{71}X_2^{176}$.$3$. After another $\alpha$-decay,the mass number decreases by $4$ and the atomic number decreases by $2$: $_{71}X_2^{176} \xrightarrow{\alpha} _{69}X_3^{172}$.$4$. After $\gamma$-decay,there is no change in mass number or atomic number: $_{69}X_3^{172} \xrightarrow{\gamma} _{69}X_4^{172}$.Therefore,the mass number of $X_4$ is $172$ and the atomic number is $69$.

$A$ radioactive nucleus decays as follows. If the atomic number of $X$ is $72$ and the mass number is $180$,what are the mass number and atomic number of $X_4$?
$X \xrightarrow{\alpha} X_1 \xrightarrow{\beta} X_2 \xrightarrow{\alpha} X_3 \xrightarrow{\gamma} X_4$

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$A$ radioactive nucleus decays as follows. If the atomic number of $X$ is $72$ and the mass number is $180$,what are the mass number and atomic number of $X_4$?$X \xrightarrow{\alpha} X_1 \xrightarrow{\beta} X_2 \xrightarrow{\alpha} X_3 \xrightarrow{\gamma} X_4$