The energy released per fission of uranium is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy released per fission is $E = 200 \, MeV$.Converting this to Joules: $E = 200 	imes 1.6 	imes 10^{-13} \, J = 3.2 	imes 10^{-11} \, J

Vedclass · Accepted Answer

$6.25 	imes 10^{16}$

Vedclass · Answer

(D) The energy released per fission is $E = 200 \, MeV$.Converting this to Joules: $E = 200 	imes 1.6 	imes 10^{-13} \, J = 3.2 	imes 10^{-11} \, J$.The power required is $P = 2 \, MW = 2 	imes 10^6 \, W$ (Joules per second).The number of fissions per second $n$ is given by the ratio of total power to energy per fission:$n = \frac{P}{E} = \frac{2 	imes 10^6 \, J/s}{3.2 	imes 10^{-11} \, J/fission}$.$n = 0.625 	imes 10^{17} = 6.25 	imes 10^{16} \, 	ext{fissions/second}$.

The energy released per fission of uranium is $200 \, MeV$. How many fissions per second are required to produce a power of $2 \, MW$?

Similar Questions

The principle of controlled chain reaction is used in

$A$ $\gamma$-ray photon creates an electron-positron pair. If the rest mass energy of an electron is $0.51 \, MeV$ and the total kinetic energy of the electron-positron pair is $0.78 \, MeV$,then the energy of the $\gamma$-ray photon in $MeV$ is:

Which of the following statement$(s)$ is/are correct?

In a nuclear fusion process,if the masses of the reactant nuclei are $m_1$ and $m_2$,and the mass of the resulting nucleus is $m_3$,then which of the following is true?

The best neutron moderator is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module