The binding energy of a deuteron is 2.2 , MeV | vedclass

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(A) The nuclear fusion reaction is given by: $2(_1^2H) \rightarrow _2^4He + Q$.The energy released $(Q)$ in a nuclear reaction is equal to the differe

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$23.6$

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(A) The nuclear fusion reaction is given by: $2(_1^2H) ightarrow _2^4He + Q$.The energy released $(Q)$ in a nuclear reaction is equal to the difference between the total binding energy of the products and the total binding energy of the reactants.$Q = (B.E. 	ext{ of } _2^4He) - 2 	imes (B.E. 	ext{ of } _1^2H)$.Given: $B.E. 	ext{ of } _2^4He = 28 \, MeV$ and $B.E. 	ext{ of } _1^2H = 2.2 \, MeV$.$Q = 28 - 2 	imes 2.2$.$Q = 28 - 4.4 = 23.6 \, MeV$.

The binding energy of a deuteron is $2.2 \, MeV$ and the binding energy of $_2^4He$ is $28 \, MeV$. If two deuterons fuse to form a $_2^4He$ nucleus,the energy released is ...... $MeV$.

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