The binding energy per nucleon for deuteron $(_1H^2)$ and helium $(_2He^4)$ are $1.1 \, MeV$ and $7 \, MeV$ respectively. When two deuterons fuse to form a helium nucleus,the energy released is ........... $MeV$.

The binding energy per nucleon for a deuteron and helium are $1.1 \, MeV$ and $7 \, MeV$ respectively. If two deuteron nuclei fuse to form one helium nucleus,the energy released is $...... \, MeV$.

Consider the nuclear fission reaction ${ }_0^1 n+{ }_{92}^{235} U \longrightarrow{ }_{56}^{144} Ba+{ }_{36}^{89} Kr+3{ }_0^1 n$. Assuming all the kinetic energy is carried away by the fast neutrons only and total binding energies of ${ }_{92}^{235} U, { }_{56}^{144} Ba$ and ${ }_{36}^{89} Kr$ to be $1800 \ MeV, 1200 \ MeV$ and $780 \ MeV$ respectively,the average kinetic energy carried by each fast neutron is (in $MeV$):

In the nuclear fusion reaction $_1^2H + _1^3H \to _2^4He + n$,given that the repulsive potential energy between the two nuclei is $7.7 \times 10^{-14} \ J$,the temperature at which the gases must be heated to initiate the reaction is nearly? [Boltzmann's constant $k = 1.38 \times 10^{-23} \ J/K$]

For nuclei with mass number close to $119$ and $238$, the binding energies per nucleon are approximately $7.6 \text{ MeV}$ and $8.6 \text{ MeV}$ respectively. If a nucleus of mass number $238$ breaks into two nuclei of nearly equal masses, what will be the approximate amount of energy released in the process of fission (in $\text{ MeV}$)?

The nucleus of $_6C^{12}$ absorbs a neutron and emits a $\beta$-particle. The resulting nucleus is ........