(B) $1$. In a uniform electric field $E$, the force on the positive charge is $F_+ = qE$ and the force on the negative charge is $F_- = -qE$.$2$. The

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(B) $1$. In a uniform electric field $E$, the force on the positive charge is $F_+ = qE$ and the force on the negative charge is $F_- = -qE$.$2$. The net force on the dipole is $F_{net} = F_+ + F_- = qE - qE = 0$.$3$. The potential energy $U$ of a dipole in an electric field is given by $U = -p \cdot E = -pE \cos \theta$.$4$. When the dipole moment $p$ is aligned with the electric field $E$, the angle $\theta = 0^\circ$.$5$. Thus, $U = -pE \cos(0^\circ) = -pE$, which is the minimum possible potential energy.

Class 12 Physics Electric Charges and Fields Electric Dipole and Electric Field

Easy

An electric dipole has a charge of magnitude $q$ and a dipole moment $p$. It is placed in a uniform electric field $E$. If its dipole moment is aligned with the direction of the electric field, the force acting on it and its potential energy will be, respectively:

A
$qE$ and $-pE$
B
Zero and minimum
C
$qE$ and minimum
D
$2qE$ and minimum

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Electric Charges and Fields

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Electric Dipole and Electric Field

If the magnitude of the intensity of the electric field at a distance $x$ on the axial line and at a distance $y$ on the equatorial line for a given electric dipole are equal,then the ratio $x:y$ is:

Medium

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For an electric dipole, if the magnitude of each charge is $10^{-10} \, \text{stC}$ and the distance between them is $1 \, \mathring{A}$, then the dipole moment is:

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Two charges $10 \mu C$ and $-10 \mu C$ are placed at points $A$ and $B$ separated by a distance of $10 \ cm$. Find the electric field at a point $P$ on the perpendicular bisector of $AB$,at a distance of $12 \ cm$ from its midpoint.

MediumAP EAMCET 2021

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For a dipole with charge $q = 2 \times 10^{-6} \, C$ and separation $d = 0.01 \, m$,calculate the maximum torque acting on this dipole if it is placed in an electric field $E = 5 \times 10^5 \, N/C$.

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Two charges of $-4 \ \mu C$ and $+4 \ \mu C$ are placed at the points $A(1, 0, 4) \ m$ and $B(2, -1, 5) \ m$ located in an electric field $\vec{E} = 0.20 \ \hat{i} \ V/cm$. The magnitude of the torque acting on the dipole is $8 \sqrt{\alpha} \times 10^{-5} \ Nm$. Where $\alpha = $ . . . . . .

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An electric dipole has a charge of magnitude $q$ and a dipole moment $p$. It is placed in a uniform electric field $E$. If its dipole moment is aligned with the direction of the electric field, the force acting on it and its potential energy will be, respectively:

Similar Questions

If the magnitude of the intensity of the electric field at a distance $x$ on the axial line and at a distance $y$ on the equatorial line for a given electric dipole are equal,then the ratio $x:y$ is:

For an electric dipole, if the magnitude of each charge is $10^{-10} \, \text{stC}$ and the distance between them is $1 \, \mathring{A}$, then the dipole moment is:

Two charges $10 \mu C$ and $-10 \mu C$ are placed at points $A$ and $B$ separated by a distance of $10 \ cm$. Find the electric field at a point $P$ on the perpendicular bisector of $AB$,at a distance of $12 \ cm$ from its midpoint.

For a dipole with charge $q = 2 \times 10^{-6} \, C$ and separation $d = 0.01 \, m$,calculate the maximum torque acting on this dipole if it is placed in an electric field $E = 5 \times 10^5 \, N/C$.

Two charges of $-4 \ \mu C$ and $+4 \ \mu C$ are placed at the points $A(1, 0, 4) \ m$ and $B(2, -1, 5) \ m$ located in an electric field $\vec{E} = 0.20 \ \hat{i} \ V/cm$. The magnitude of the torque acting on the dipole is $8 \sqrt{\alpha} \times 10^{-5} \ Nm$. Where $\alpha = $ . . . . . .

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