In $Millikan's$ oil drop experiment,a charge $Q$ is held stationary between two plates under a potential difference of $2400\, V$. If a second drop with half the radius is to be held stationary using a potential difference of $600\, V$,then the charge on the second drop is:

  • A
    $Q/4$
  • B
    $Q/2$
  • C
    $Q$
  • D
    $3Q/2$

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