Two identical spherical conductors B and C ha | vedclass

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(D) Let the initial charge on each sphere $B$ and $C$ be $q$ and the distance between them be $r$. The initial force is $F = \frac{kq^2}{r^2}$.When un

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$3F/8$

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(D) Let the initial charge on each sphere $B$ and $C$ be $q$ and the distance between them be $r$. The initial force is $F = \frac{kq^2}{r^2}$.When uncharged sphere $A$ is brought in contact with $B$,the charge on $B$ becomes $q/2$ and on $A$ becomes $q/2$.Now,when sphere $A$ (having charge $q/2$) is brought in contact with $C$ (having charge $q$),the total charge is $q + q/2 = 3q/2$. Since the spheres are identical,the charge is shared equally,so each gets $(3q/2) / 2 = 3q/4$.Now,the charge on $B$ is $q/2$ and the charge on $C$ is $3q/4$.The new force $F' = \frac{k(q/2)(3q/4)}{r^2} = \frac{3kq^2}{8r^2}$.Since $F = \frac{kq^2}{r^2}$,we get $F' = \frac{3}{8}F$.

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