Two capacitors $C_1$ and $C_2$ are charged to $120 \ V$ and $200 \ V$ respectively. It is found that by connecting them together,the potential on each can be made zero. Then:
- A$5C_1 = 3C_2$
- B$3C_1 = 5C_2$
- C$3C_1 + 5C_2 = 0$
- D$9C_1 = 4C_2$
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