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(C) The electric field lines point from higher potential to lower potential. Since the electric field is uniform and directed towards the right,the po

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$V_A = V_C, V_B < V_D$

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(C) The electric field lines point from higher potential to lower potential. Since the electric field is uniform and directed towards the right,the potential decreases as we move along the direction of the electric field. Points $A$ and $C$ lie on the same vertical line perpendicular to the electric field lines,so they are at the same potential,i.e.,$V_A = V_C$. Point $D$ is at a position where the potential is higher than at point $B$ because the electric field is directed from $D$ towards $B$. Therefore,$V_D > V_B$ or $V_B Combining these,we get $V_A = V_C$ and $V_B < V_D$.

$A$ circle of radius $R$ is drawn in a uniform electric field as shown in the figure. If the potentials at points $A, B, C,$ and $D$ on the circumference of the circle are $V_A, V_B, V_C,$ and $V_D$ respectively,then:

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