A parallel plate capacitor is formed by conne | vedclass

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(A) In a system of $n$ plates connected alternately,we form $(n - 1)$ capacitors in parallel.Each capacitor is formed by two adjacent plates,and the c

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$(n - 1)C$

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(A) In a system of $n$ plates connected alternately,we form $(n - 1)$ capacitors in parallel.Each capacitor is formed by two adjacent plates,and the capacitance of each such pair is given as $C$.Since the plates are connected alternately,all these $(n - 1)$ capacitors are connected in parallel.The equivalent capacitance $C_{eq}$ for capacitors in parallel is the sum of individual capacitances:$C_{eq} = C_1 + C_2 + ... + C_{n-1}$Since each $C_i = C$,we have:$C_{eq} = (n - 1)C$.

$A$ parallel plate capacitor is formed by connecting $n$ plates placed at equal distances alternately. If the capacitance between any two adjacent plates is $C$,find the resultant capacitance.

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