For an electric dipole with charge q = 2 time | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The dipole moment $p$ is given by the product of the charge $q$ and the separation distance $d$:$p = q 	imes d = (2 	imes 10^{-6} \ C) 	imes (0

Vedclass · Accepted Answer

$10 	imes 10^{-3} \ Nm$

Vedclass · Answer

(B) The dipole moment $p$ is given by the product of the charge $q$ and the separation distance $d$:$p = q 	imes d = (2 	imes 10^{-6} \ C) 	imes (0.01 \ m) = 2 	imes 10^{-8} \ Cm$.The torque $	au$ acting on a dipole in an electric field is given by $	au = pE \sin(	heta)$.For maximum torque,$\sin(	heta) = 1$ (when the dipole is perpendicular to the electric field).Therefore,$	au_{max} = p 	imes E$.Substituting the values:$	au_{max} = (2 	imes 10^{-8} \ Cm) 	imes (5 	imes 10^{5} \ N/C) = 10 	imes 10^{-3} \ Nm$.

For an electric dipole with charge $q = 2 \times 10^{-6} \ C$ and separation distance $d = 0.01 \ m$,if the external electric field is $E = 5 \times 10^{5} \ N/C$,calculate the maximum torque acting on the dipole.

Similar Questions

$A$ given charge situated at a distance $r$ from an electric dipole on its axis experiences a force $F$. If the distance of the charge from the dipole is doubled,the force acting on the charge will be

Two charges $+q$ and $-q$ are placed at a distance $b$ apart as shown in the figure. The electric field at a point $P$ on the perpendicular bisector as shown is

The force of interaction between two co-axial short electric dipoles whose centers are $R$ distance apart varies as:

$A$ system of three charges is placed as shown in the figure. If $D >> d$,the potential energy of the system is best given by:

Two point dipoles of dipole moments $\vec{p}_1$ and $\vec{p}_2$ are at a distance $x$ from each other,and $\vec{p}_1 \parallel \vec{p}_2$. The force between the dipoles is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module