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(A) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate.Let the inputs be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$

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(A) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate.Let the inputs be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$ and $\bar{B}$.These are fed into a $NOR$ gate,so the final output $Y$ is given by the Boolean expression:$Y = \overline{\bar{A} + \bar{B}}$Using De Morgan's Law,$\overline{\bar{A} + \bar{B}} = \overline{\bar{A}} \cdot \overline{\bar{B}} = A \cdot B$.Thus,the circuit acts as an $AND$ gate.By analyzing the input waveforms:$1$. When both $A$ and $B$ are $1$ (high),the output $Y$ is $1$.$2$. In all other cases,the output $Y$ is $0$.Comparing this with the given options,the waveform that represents the $AND$ operation of inputs $A$ and $B$ is correct.

The input waveforms for the given circuit are shown. Which of the following output waveforms is correct?

Similar Questions

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