$A$ transistor is connected in a common emitter configuration with $R_o = 4 \text{ k}\Omega$,$R_i = 1 \text{ k}\Omega$,$I_C = 1 \text{ mA}$,and $I_b = 20 \text{ }\mu\text{A}$. The voltage gain is:

The graph between the input voltage $(V_{i})$ and the output voltage $(V_{o})$ of a transistor connected in common emitter configuration is shown in the figure. The active, saturation and cutoff regions of the transistor are respectively

If $ \alpha $-current gain of a transistor is $ 0.98 $,what is the value of $ \beta $-current gain of the transistor?

$A$ transistor has a voltage gain '$A$'. If a fraction '$\beta$' of its output is fed back to the input of the transistor,then the transistor becomes an oscillator when:

For a common base circuit,if $\frac{I_C}{I_E} = 0.98$,then the current gain for a common emitter circuit will be:

If a transistor having $\alpha = 0.9$ is used in $CE$ configuration, then for a change of $0.4 \text{ mA}$ in base current, what will be the change in collector current (in $\text{ mA}$)?