What is the voltage gain of a common-emitter amplifier with an input resistance of $3 \ \Omega$ and a load resistance of $24 \ \Omega$? (Given $\beta = 6$)
- A$2.2$
- B$1.2$
- C$4.8$
- D$48$
Explore More
Similar Questions
For a transistor,$\frac{1}{\alpha_{DC}} - \frac{1}{\beta_{DC}}$ is equal to [where $\alpha_{DC}$ and $\beta_{DC}$ are current amplification factors].
DifficultMHT CET 2021
View SolutionIn the following transistor circuit,$R_i$ is the input resistance and $R_0$ is the output resistance. The approximate voltage gain for the circuit is:
Medium
View SolutionAn oscillator is nothing but an amplifier with
MediumAIIMS 2014
View SolutionIn a $CB$ amplifier,the collector current is $5.488 \ mA$ and the emitter current is $5.6 \ mA$. The current gain $(\beta)$ of this transistor will be .......
Medium
View SolutionIn a transistor (common emitter configuration) the ratio of power gain to voltage gain is ($\alpha$ and $\beta$ are current ratios)
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo