The slope of the anode characteristic and the mutual characteristic of a triode are $0.02 \text{ mA/V}$ and $1 \text{ mA/V}$ respectively. The amplification factor of the valve is:

For a triode,at ${V_g} = -1 \text{ V}$,the following observations were taken: ${V_p} = 75 \text{ V}, {I_p} = 2 \text{ mA}$ and ${V_p} = 100 \text{ V}, {I_p} = 4 \text{ mA}$. The value of plate resistance will be ...... $k\Omega$.

In a triode,the cathode,grid,and plate are at potentials of $0 \, V$,$-2 \, V$,and $80 \, V$ respectively. Electrons are emitted from the cathode with an initial kinetic energy of $3 \, eV$. What is the energy of the electron when it reaches the plate in $eV$?

The correct relation for a triode is:

The plate current $i_p$ in a triode valve is given by $i_p = K(V_p + \mu V_g)^{3/2}$,where $i_p$ is in $mA$ and $V_p$ and $V_g$ are in $V$. If $r_p = 10^4 \, \Omega$ and $g_m = 5 \times 10^{-3} \, \text{mho}$,then for $i_p = 8 \, mA$ and $V_p = 300 \, V$,what are the values of $K$ and the grid cut-off voltage?

The amplification factor of a triode valve is $15$. If the grid voltage is changed by $0.3 \,V$,what is the change in plate voltage required to keep the plate current constant (in $V$)?