When a transistor is used as a $CB$ transistor amplifier,the current gain is $0.8$. If the change in base current is $6 \ mA$,then the change in collector current is ....... $mA$.

The input signal given to a $C.E.$ amplifier having a voltage gain of $126$ is $V_i = 2 \cos \left(12 t + \frac{\pi}{3}\right)$. The corresponding output signal will be

$A$ common emitter transistor amplifier has a current gain of $50$. If the load resistance is $4 \ k\Omega$ and input resistance is $500 \ \Omega$, the voltage gain of the amplifier is

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

According to a graph drawn between the input and output voltages of a transistor connected in common emitter configuration, the region in which the transistor acts as a switch is

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.