The angle of deviation $\delta$ produced by a prism of refractive index $\mu$ and small refracting angle $A$ is given by:

$A$ ray of light is incident at an angle '$i$' on one face of a prism of small angle '$A$' and emerges normally from the other surface. If '$\mu$' is the refractive index of the material of the prism,then the angle of incidence is:

In the diagram,a prism of angle $30^o$ is used. $A$ ray $PQ$ is incident as shown. An emergent ray $RS$ emerges perpendicular to the second face. The angle of deviation is.....$^o$

$A$ ray of light passing through a prism $(\mu = \sqrt{3})$ suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. Then,the angle of prism is ..... (in degrees).

$A$ ray of light suffers minimum deviation when incident on a prism having an angle of the prism equal to $60^{\circ}$. The refractive index of the prism material is $\sqrt{2}$. The angle of incidence (in degrees) is . . . . . . .

Two beams of red and violet colours are made to pass separately through a prism of $A=60^{\circ}$. In the minimum deviation position,the angle of refraction inside the prism will be