A combination of two prisms,one of flint glas | vedclass

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(C) For dispersion without deviation,the condition is $(\mu - 1)A + (\mu' - 1)A' = 0$.Given: $A = 15^\circ$,$\mu = 1.65$,$\omega = 0.03$ (flint) and $

Vedclass · Accepted Answer

$0.0975$

Vedclass · Answer

(C) For dispersion without deviation,the condition is $(\mu - 1)A + (\mu' - 1)A' = 0$.Given: $A = 15^\circ$,$\mu = 1.65$,$\omega = 0.03$ (flint) and $\mu' = 1.52$,$\omega' = 0.02$ (crown).Substituting the values: $(1.65 - 1) 	imes 15^\circ + (1.52 - 1) 	imes A' = 0$.$0.65 	imes 15^\circ + 0.52 	imes A' = 0$.$A' = -\frac{0.65 	imes 15^\circ}{0.52} = -18.75^\circ$.The negative sign indicates that the prisms are placed in opposition.The net angular dispersion is given by $\delta_{	heta} = \omega(\mu - 1)A + \omega'(\mu' - 1)A'$.Since $(\mu - 1)A = -(\mu' - 1)A'$,we have $\delta_{	heta} = \omega(\mu - 1)A - \omega'(\mu - 1)A = (\omega - \omega')(\mu - 1)A$.$\delta_{	heta} = (0.03 - 0.02) 	imes (1.65 - 1) 	imes 15^\circ$.$\delta_{	heta} = 0.01 	imes 0.65 	imes 15^\circ = 0.0975^\circ$.

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