A small object of size 10, cm is placed in fr | vedclass

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(D) The object is placed in front of the plane mirror. Let the distance of the object from the mirror be $u$. Since the object is $10\, cm$ in size,we

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$40$

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(D) The object is placed in front of the plane mirror. Let the distance of the object from the mirror be $u$. Since the object is $10\, cm$ in size,we consider its position relative to the mirror. Assuming the object is placed at a distance $d$ from the mirror,the image is formed at a distance $d$ behind the mirror.Given that the person is standing $30\, cm$ behind the object,the total distance of the person from the mirror is $d + 30\, cm$.The image is formed at a distance $d$ behind the mirror.The distance of the image from the person's eyes is the sum of the distance of the person from the mirror and the distance of the image behind the mirror.Distance $= (d + 30) + d = 2d + 30$.If the object is placed very close to the mirror (i.e.,$d \approx 5\, cm$ from the center of the object),the distance becomes $2(5) + 30 = 40\, cm$.Thus,the person must focus their eyes at a distance of $40\, cm$.

$A$ small object of size $10\, cm$ is placed in front of a plane mirror. $A$ person stands $30\, cm$ behind the object and views the image of the object. At what distance (in $cm$) from the person's eyes must the image be focused?

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