When unpolarized light is incident from air onto glass $(\mu = 1.5)$,then:

Critical angle for a certain medium is $\sin ^{-1}(0.6)$. The polarizing angle of that medium is

$A$ ray of unpolarised light is incident on a glass surface of refractive index $1.73$ at the polarizing angle. The angle of refraction will be. [Take $\tan 60^{\circ} = 1.73$] (in $^{\circ}$)

When a light ray is incident on the surface of a medium,the reflected ray is completely polarized. Then the angle between the reflected and refracted rays is (in $^{\circ}$)

An unpolarized light is incident on the plane interface of an air-dielectric medium as shown in the figure. If the incident angle is equal to the Brewster angle, identify the expression representing the reflected wave.

Unpolarised light is incident on the boundary between two dielectric media,whose dielectric constants are $2.8$ (medium $1$) and $6.8$ (medium $2$),respectively. To satisfy the condition that the reflected and refracted rays are perpendicular to each other,the angle of incidence should be $\tan ^{-1}\left(1+\frac{10}{\theta}\right)^{\frac{1}{2}}$. The value of $\theta$ is $.............$ (Given for dielectric media,$\mu_{r}=1$)