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(C) The formula for dispersive power is $\omega = \frac{\mu_v - \mu_r}{\mu_y - 1}$.First,we calculate the mean refractive index $\mu_y$ using the form

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$0.019$

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(C) The formula for dispersive power is $\omega = \frac{\mu_v - \mu_r}{\mu_y - 1}$.First,we calculate the mean refractive index $\mu_y$ using the formula $\mu_y = \frac{\mu_v + \mu_r}{2}$.Substituting the given values: $\mu_y = \frac{1.52 + 1.51}{2} = \frac{3.03}{2} = 1.515$.Now,substitute $\mu_y$,$\mu_v$,and $\mu_r$ into the dispersive power formula:$\omega = \frac{1.52 - 1.51}{1.515 - 1} = \frac{0.01}{0.515} \approx 0.0194$.Rounding to the given options,the correct value is $0.019$.

The prism angle of a prism is $10^{\circ}$. The refractive indices for red and violet colors are $1.51$ and $1.52$ respectively. The dispersive power will be .....

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