An equilateral prism $P$ produces a minimum deviation for a given light ray. Additional prisms $Q$ and $R$ of the same shape and material are placed as shown in the figure. The ray will experience:

An isosceles prism of angle $120^\circ$ has a refractive index of $1.44$. Two parallel monochromatic rays enter the prism parallel to each other in air as shown. The rays emerging from the opposite faces

Two equilateral-triangular prisms $P_1$ and $P_2$ are kept with their sides parallel to each other,in vacuum,as shown in the figure. $A$ light ray enters prism $P_1$ at an angle of incidence $\theta$ such that the outgoing ray undergoes minimum deviation in prism $P_2$. If the respective refractive indices of $P_1$ and $P_2$ are $\sqrt{\frac{3}{2}}$ and $\sqrt{3}$,then $\theta = \sin^{-1}\left[\sqrt{\frac{3}{2}} \sin \left(\frac{\pi}{\beta}\right)\right]$,where the value of $\beta$ is:

How is the graph between the angle of deviation $(\delta)$ and the angle of incidence $(i)$ represented for a triangular prism?

$A$ flint glass prism is joined with a crown glass prism to produce dispersion without deviation. The refractive indices of these for mean rays are $1.602$ and $1.500$ respectively. If the angle of the flint glass prism is $10^{\circ}$,then the angle of the crown glass prism will be:

$A$ ray of light is incident on the first face of an equilateral glass prism at an angle of incidence '$i$'. The emergent ray just grazes along the adjacent face. The refractive index of the prism is $\sqrt{2}$. The value of the angle of incidence at the first face is $(\sin 45^{\circ} = 1/\sqrt{2}, \sin 90^{\circ} = 1)$.