A beam of light is converging towards a point | vedclass

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(D) For this situation,the incident rays are converging towards a point $O$ behind the mirror,which acts as a virtual object.Here,the object distance

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$20$

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(D) For this situation,the incident rays are converging towards a point $O$ behind the mirror,which acts as a virtual object.Here,the object distance $u = +10 \, cm$ (since it is behind the mirror) and the focal length of the convex mirror $f = +20 \, cm$.Using the mirror formula: $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$Substituting the values: $\frac{1}{v} + \frac{1}{10} = \frac{1}{20}$$\frac{1}{v} = \frac{1}{20} - \frac{1}{10} = \frac{1 - 2}{20} = -\frac{1}{20}$Therefore,$v = -20 \, cm$.The negative sign indicates that the image is formed in front of the mirror at a distance of $20 \, cm$ from the pole.

$A$ beam of light is converging towards a point $O$ behind a convex mirror of focal length $20 \, cm$. If the point $O$ is $10 \, cm$ behind the mirror,then the position of the image is at a distance of ..... $cm$.

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