Three prisms 1, 2, and 3 have a prism angle A | vedclass

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(A) For a thin prism,the angle of deviation $\delta$ is given by the formula $\delta = (\mu - 1)A$.Since the prism angle $A = 60^{\circ}$ is the same

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$\delta_3 > \delta_2 > \delta_1$

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(A) For a thin prism,the angle of deviation $\delta$ is given by the formula $\delta = (\mu - 1)A$.Since the prism angle $A = 60^{\circ}$ is the same for all three prisms,the angle of deviation $\delta$ is directly proportional to the refractive index $\mu$ of the material of the prism $(\delta \propto \mu - 1)$.Given refractive indices are $\mu_1 = 1.4$,$\mu_2 = 1.5$,and $\mu_3 = 1.6$.Comparing the refractive indices: $\mu_3 > \mu_2 > \mu_1$.Therefore,the angles of deviation follow the same order: $\delta_3 > \delta_2 > \delta_1$.

Three prisms $1, 2,$ and $3$ have a prism angle $A = 60^{\circ}$. Their refractive indices are $1.4, 1.5,$ and $1.6$ respectively. If $\delta_1, \delta_2,$ and $\delta_3$ are their angles of deviation,then:

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